(2x^2+5x-3)-(2x^2+4)=38

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Solution for (2x^2+5x-3)-(2x^2+4)=38 equation:


Simplifying
(2x2 + 5x + -3) + -1(2x2 + 4) = 38

Reorder the terms:
(-3 + 5x + 2x2) + -1(2x2 + 4) = 38

Remove parenthesis around (-3 + 5x + 2x2)
-3 + 5x + 2x2 + -1(2x2 + 4) = 38

Reorder the terms:
-3 + 5x + 2x2 + -1(4 + 2x2) = 38
-3 + 5x + 2x2 + (4 * -1 + 2x2 * -1) = 38
-3 + 5x + 2x2 + (-4 + -2x2) = 38

Reorder the terms:
-3 + -4 + 5x + 2x2 + -2x2 = 38

Combine like terms: -3 + -4 = -7
-7 + 5x + 2x2 + -2x2 = 38

Combine like terms: 2x2 + -2x2 = 0
-7 + 5x + 0 = 38
-7 + 5x = 38

Solving
-7 + 5x = 38

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 5x = 38 + 7

Combine like terms: -7 + 7 = 0
0 + 5x = 38 + 7
5x = 38 + 7

Combine like terms: 38 + 7 = 45
5x = 45

Divide each side by '5'.
x = 9

Simplifying
x = 9

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